3.2973 \(\int \frac{\sqrt{a+b (c x^3)^{3/2}}}{x^{10}} \, dx\)

Optimal. Leaf size=101 \[ \frac{b^2 c^3 \tanh ^{-1}\left (\frac{\sqrt{a+b \left (c x^3\right )^{3/2}}}{\sqrt{a}}\right )}{18 a^{3/2}}-\frac{b c^3 \sqrt{a+b \left (c x^3\right )^{3/2}}}{18 a \left (c x^3\right )^{3/2}}-\frac{\sqrt{a+b \left (c x^3\right )^{3/2}}}{9 x^9} \]

[Out]

-Sqrt[a + b*(c*x^3)^(3/2)]/(9*x^9) - (b*c^3*Sqrt[a + b*(c*x^3)^(3/2)])/(18*a*(c*x^3)^(3/2)) + (b^2*c^3*ArcTanh
[Sqrt[a + b*(c*x^3)^(3/2)]/Sqrt[a]])/(18*a^(3/2))

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Rubi [A]  time = 0.065108, antiderivative size = 104, normalized size of antiderivative = 1.03, number of steps used = 6, number of rules used = 6, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.286, Rules used = {369, 266, 47, 51, 63, 208} \[ \frac{b^2 c^3 \tanh ^{-1}\left (\frac{\sqrt{a+b \left (c x^3\right )^{3/2}}}{\sqrt{a}}\right )}{18 a^{3/2}}-\frac{b c^6 x^9 \sqrt{a+b \left (c x^3\right )^{3/2}}}{18 a \left (c x^3\right )^{9/2}}-\frac{\sqrt{a+b \left (c x^3\right )^{3/2}}}{9 x^9} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[a + b*(c*x^3)^(3/2)]/x^10,x]

[Out]

-Sqrt[a + b*(c*x^3)^(3/2)]/(9*x^9) - (b*c^6*x^9*Sqrt[a + b*(c*x^3)^(3/2)])/(18*a*(c*x^3)^(9/2)) + (b^2*c^3*Arc
Tanh[Sqrt[a + b*(c*x^3)^(3/2)]/Sqrt[a]])/(18*a^(3/2))

Rule 369

Int[((d_.)*(x_))^(m_.)*((a_) + (b_.)*((c_.)*(x_)^(q_))^(n_))^(p_.), x_Symbol] :> With[{k = Denominator[n]}, Su
bst[Int[(d*x)^m*(a + b*c^n*x^(n*q))^p, x], x^(1/k), (c*x^q)^(1/k)/(c^(1/k)*(x^(1/k))^(q - 1))]] /; FreeQ[{a, b
, c, d, m, p, q}, x] && FractionQ[n]

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 47

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + 1)), x] - Dist[(d*n)/(b*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d},
x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && LtQ[m, -1] &&  !(IntegerQ[n] &&  !IntegerQ[m]) &&  !(ILeQ[m + n + 2, 0
] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c, d, m, n, x]

Rule 51

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*(m + n + 2))/((b*c - a*d)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && LtQ[m, -1] &&  !(LtQ[n, -1] && (EqQ[a, 0] || (NeQ[
c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rubi steps

\begin{align*} \int \frac{\sqrt{a+b \left (c x^3\right )^{3/2}}}{x^{10}} \, dx &=\operatorname{Subst}\left (\int \frac{\sqrt{a+b c^{3/2} x^{9/2}}}{x^{10}} \, dx,\sqrt{x},\frac{\sqrt{c x^3}}{\sqrt{c} x}\right )\\ &=\operatorname{Subst}\left (\frac{2}{9} \operatorname{Subst}\left (\int \frac{\sqrt{a+b c^{3/2} x}}{x^3} \, dx,x,x^{9/2}\right ),\sqrt{x},\frac{\sqrt{c x^3}}{\sqrt{c} x}\right )\\ &=-\frac{\sqrt{a+b \left (c x^3\right )^{3/2}}}{9 x^9}+\operatorname{Subst}\left (\frac{1}{18} \left (b c^{3/2}\right ) \operatorname{Subst}\left (\int \frac{1}{x^2 \sqrt{a+b c^{3/2} x}} \, dx,x,x^{9/2}\right ),\sqrt{x},\frac{\sqrt{c x^3}}{\sqrt{c} x}\right )\\ &=-\frac{\sqrt{a+b \left (c x^3\right )^{3/2}}}{9 x^9}-\frac{b c^6 x^9 \sqrt{a+b \left (c x^3\right )^{3/2}}}{18 a \left (c x^3\right )^{9/2}}-\operatorname{Subst}\left (\frac{\left (b^2 c^3\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+b c^{3/2} x}} \, dx,x,x^{9/2}\right )}{36 a},\sqrt{x},\frac{\sqrt{c x^3}}{\sqrt{c} x}\right )\\ &=-\frac{\sqrt{a+b \left (c x^3\right )^{3/2}}}{9 x^9}-\frac{b c^6 x^9 \sqrt{a+b \left (c x^3\right )^{3/2}}}{18 a \left (c x^3\right )^{9/2}}-\operatorname{Subst}\left (\frac{\left (b c^{3/2}\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{a}{b c^{3/2}}+\frac{x^2}{b c^{3/2}}} \, dx,x,\sqrt{a+b c^{3/2} x^{9/2}}\right )}{18 a},\sqrt{x},\frac{\sqrt{c x^3}}{\sqrt{c} x}\right )\\ &=-\frac{\sqrt{a+b \left (c x^3\right )^{3/2}}}{9 x^9}-\frac{b c^6 x^9 \sqrt{a+b \left (c x^3\right )^{3/2}}}{18 a \left (c x^3\right )^{9/2}}+\frac{b^2 c^3 \tanh ^{-1}\left (\frac{\sqrt{a+b \left (c x^3\right )^{3/2}}}{\sqrt{a}}\right )}{18 a^{3/2}}\\ \end{align*}

Mathematica [F]  time = 0.0495551, size = 0, normalized size = 0. \[ \int \frac{\sqrt{a+b \left (c x^3\right )^{3/2}}}{x^{10}} \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[Sqrt[a + b*(c*x^3)^(3/2)]/x^10,x]

[Out]

Integrate[Sqrt[a + b*(c*x^3)^(3/2)]/x^10, x]

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Maple [F]  time = 0.059, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{{x}^{10}}\sqrt{a+b \left ( c{x}^{3} \right ) ^{{\frac{3}{2}}}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*(c*x^3)^(3/2))^(1/2)/x^10,x)

[Out]

int((a+b*(c*x^3)^(3/2))^(1/2)/x^10,x)

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*(c*x^3)^(3/2))^(1/2)/x^10,x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*(c*x^3)^(3/2))^(1/2)/x^10,x, algorithm="fricas")

[Out]

Timed out

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{a + b \left (c x^{3}\right )^{\frac{3}{2}}}}{x^{10}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*(c*x**3)**(3/2))**(1/2)/x**10,x)

[Out]

Integral(sqrt(a + b*(c*x**3)**(3/2))/x**10, x)

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Giac [A]  time = 1.41312, size = 158, normalized size = 1.56 \begin{align*} -\frac{1}{18} \, b^{2} c^{\frac{13}{2}}{\left (\frac{\arctan \left (\frac{\sqrt{\sqrt{c x} b c^{4} x^{4} + a c^{3}}}{\sqrt{-a c} c}\right )}{\sqrt{-a c} a c^{4}} + \frac{\sqrt{\sqrt{c x} b c^{4} x^{4} + a c^{3}} a c^{3} +{\left (\sqrt{c x} b c^{4} x^{4} + a c^{3}\right )}^{\frac{3}{2}}}{a b^{2} c^{12} x^{9}}\right )}{\left | c \right |} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*(c*x^3)^(3/2))^(1/2)/x^10,x, algorithm="giac")

[Out]

-1/18*b^2*c^(13/2)*(arctan(sqrt(sqrt(c*x)*b*c^4*x^4 + a*c^3)/(sqrt(-a*c)*c))/(sqrt(-a*c)*a*c^4) + (sqrt(sqrt(c
*x)*b*c^4*x^4 + a*c^3)*a*c^3 + (sqrt(c*x)*b*c^4*x^4 + a*c^3)^(3/2))/(a*b^2*c^12*x^9))*abs(c)